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Discussion Starter · #1 ·
Now, me, having owned pump shotguns for years, you would think I know the answer to this really easy question. I think I am overthinking this one though. So:

I take my Mossberg 590 out and look at it, load a few rounds, and rack the action, and a shell pops on to the elevator, about to go in to the tube right? Fine. Here is where I get confused. When the action is closed, the cartridge interrupter stops the shells from coming out of the mag tube. When you open it, the interrupter moves out of the way and pops a shell on the the elevator. My question is...what stops more then one shell from coming out? o_O I mean, I clearly see the interrupter move out of the way, pop the shell out, and after the shell is popped on the the elevator...the interrupter is STILL back, and stays that way until the action is closed. Why does only one shell pop out?

I know, silly, but I have always wondered that about pump action shotguns. :(
 

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Discussion Starter · #3 ·
Does nobody actually know the forces of black magic that causes this to happen? xD
 

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Discussion Starter · #5 ·
It may be a start though. ;)
 

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Discussion Starter · #9 ·
What about Ithaca 37's and Browning BPS shotguns?! Ejecting a spent shell, and releasing a fresh shell from the magazine tube through the same port at practically the same time!! How did they figure that out!
YEAH! My friend has an Ithaca that does that too!

My God. I think we have uncovered a great Pump-Shotgun Conspiracy...
 

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Discussion Starter · #11 ·
Upon further inspection, CamoColton is right. There is another "Cartridge interrupter" on the other side. The shotgun would have gotten away with it too if it wasn't for those meddling kids. Great mystery solved. :)
 
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